Chemistry 11

Today we reviewed the Solutions Unit by looking at solubilities of polar and non-polar solutes and solvents.  We did the lab:  16A Polar and Non-polar solutes and solvents.   Do all questions #1-5 at the end of the lab.  No conclusion or follow-up questions.

Some answers to selected Unit 6 Solutions Review Assignment:
2) Solvent is water and solute is salt.
3) Polar solutes and ionic solutes will dissolve in polar solvents, non-polar solutes will dissolve in non-polar solvents.

4a) polar solvent= water             c) a non-polar solute = iodine crystals          e) ionic solute = salt

5b) (NH₄)₃PO₄ -------3NH₄⁺ + PO₄^-3

6b) H₂SO₄ + H₂O -----------H₃O⁺ + HSO₄^- 

^{assume that only one H leaves the acid each time} 

7a) [Na⁺]= 2 x 0.25 M = 0.50 M  [CO₃^-2] = 0.25 M

8) Two kinds of double replacement reactions are precipitation reactions and acid/base neutralizations

9 and 10 a) 

Molecular:  Na₂SO_4(aq)  + Pb(NO₃)_2(aq) -----------PbSO_4(s) +  2NaNO_3(aq)

 

Total ionic:   2Na⁺_(aq) + SO₄^-2_(aq) + Pb⁺²_(aq) + 2NO₃^-_(aq) ---------PbSO_4(s)  +  2Na⁺ + 2NO_{3 (aq)}

  

Net ionic:  Pb⁺²_(aq) + SO₄^-2_(aq) ---------PbSO_4(s)

12) b is a acid       c and e are bases      d and f are neither  

14) ionic solutes will conduct electricity in solution so if you know that the solute is ionic then you know that the solution formed with this solute 

15) [NaCl] = 0.00085 M                    17) Final concentration = 0.13 M

19) 75.0 mL of 2.00 M HCl         21) 0.93 M
 

23) 22.8 g of NaOH